To find the probability that a student sings in the choir or plays for the school basketball team, we can use the formula for the probability of the union of two events:
\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]
Where:
- \( P(A) \) is the probability that a student is in the choir.
- \( P(B) \) is the probability that a student plays for the basketball team.
- \( P(A \cap B) \) is the probability that a student is both in the choir and on the basketball team.
Given:
- \( P(A) = 0.09 \)
- \( P(B) = 0.08 \)
- \( P(A \cap B) = 0.01 \)
Now we can substitute these values into the formula:
\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]
Calculating each term: \[ P(A \cup B) = 0.09 + 0.08 - 0.01 \]
\[ P(A \cup B) = 0.17 - 0.01 \]
\[ P(A \cup B) = 0.16 \]
Thus, the probability that a student sings in the choir or plays for the school basketball team is 0.16.
The correct answer is: 0.16