To determine which circuit has the highest current with the given voltage sources, we must consider Ohm's Law, which states:
\[ I = \frac{V}{R} \]
Where:
- \( I \) is the current,
- \( V \) is the voltage,
- \( R \) is the resistance.
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Circuit: Wires, a 9V battery, no resistors
- This circuit has no resistors, which means it effectively has a very low resistance. The current would be extremely high, theoretically approaching infinity depending on the resistance of the wires and the internal resistance of the battery.
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Circuit: Wires, a 9V battery, a light bulb
- The light bulb adds some resistance to the circuit. This will reduce the current compared to the first circuit. The exact current depends on the bulb's resistance, which will likely lead to a finite and lower current compared to the first scenario.
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Circuit: Wires, a 1.5V battery, no resistors
- Similar to the first circuit but with a lower voltage. Even with negligible resistance, the current will be much lower because of the 1.5V battery.
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Circuit: Wires, a 1.5V battery, a light bulb
- Like before, the light bulb introduces resistance, which further reduces the current. It is also limited by the 1.5V from the battery.
Based on these considerations, the circuit with wires, a 9V battery, and no resistors will have the highest current because it has the highest voltage and essentially no resistance.