What factors does 8 have (8,1 or 4,2?) that, when one is multiplied by 3, will add/subtract to get -10?
4*3 = 12, when you subtract 2 from that product, that give you 10. Just make sure you get the signs right.
(3x+2)(x-4) = 0
Determine the zeros of the function 3x^2 -8=10x. I know I rewrite it as 3x^2 -10x-8 = 0
But then what do I do-I'm totally confused-Answers are
{-2,4}
{2,4}
{-2/3,4}
{2/3,4}
Please direct me or show the steps, just don't give me the answer because I still won't get it.
Thank you
1 answer
1 answer