Question
You are given a sphere with a diameter of 4 feet. What is the volume?
Question 3 options:
129.3 ft³
33.5 ft³
445.1 ft³
Question 3 options:
129.3 ft³
33.5 ft³
445.1 ft³
Answers
GPT-4o mini
To find the volume of a sphere, you can use the formula:
\[
V = \frac{4}{3} \pi r^3
\]
where \( V \) is the volume and \( r \) is the radius of the sphere.
Given that the diameter of the sphere is 4 feet, the radius \( r \) will be:
\[
r = \frac{\text{diameter}}{2} = \frac{4 \text{ ft}}{2} = 2 \text{ ft}
\]
Now, substitute the radius into the volume formula:
\[
V = \frac{4}{3} \pi (2)^3
\]
Calculating \( (2)^3 \):
\[
(2)^3 = 8
\]
Now substitute that into the volume formula:
\[
V = \frac{4}{3} \pi (8)
\]
\[
V = \frac{32}{3} \pi
\]
Using \( \pi \approx 3.14159 \):
\[
V \approx \frac{32}{3} \times 3.14159 \approx 33.51 \text{ ft}^3
\]
Thus, rounding to one decimal place, the volume is approximately:
\[
33.5 \text{ ft}^3
\]
So, the correct answer is:
**33.5 ft³**
\[
V = \frac{4}{3} \pi r^3
\]
where \( V \) is the volume and \( r \) is the radius of the sphere.
Given that the diameter of the sphere is 4 feet, the radius \( r \) will be:
\[
r = \frac{\text{diameter}}{2} = \frac{4 \text{ ft}}{2} = 2 \text{ ft}
\]
Now, substitute the radius into the volume formula:
\[
V = \frac{4}{3} \pi (2)^3
\]
Calculating \( (2)^3 \):
\[
(2)^3 = 8
\]
Now substitute that into the volume formula:
\[
V = \frac{4}{3} \pi (8)
\]
\[
V = \frac{32}{3} \pi
\]
Using \( \pi \approx 3.14159 \):
\[
V \approx \frac{32}{3} \times 3.14159 \approx 33.51 \text{ ft}^3
\]
Thus, rounding to one decimal place, the volume is approximately:
\[
33.5 \text{ ft}^3
\]
So, the correct answer is:
**33.5 ft³**