To find a point on the graph of the function \( y = (2x + 1)^2 - 4 \), we can choose a value for \( x \) and then compute the corresponding \( y \).
Let’s try \( x = 0 \):
\[ y = (2(0) + 1)^2 - 4 \] \[ y = (1)^2 - 4 \] \[ y = 1 - 4 \] \[ y = -3 \]
So, when \( x = 0 \), \( y = -3 \). Therefore, the point \( (0, -3) \) is on the graph of the function.
If you have specific options provided, please share them, and I can confirm which one of them is correct!