A) A cylinder has a surface area of 42π cm . If it were dilated using a scale factor of

1
2
, what is
the surface area of the new cylinder? (1 point)
2
21π cm
2
84π cm
2
10.5π cm
2
13.5π cm
2

1 answer

To find the new surface area after dilation, we first need to understand how the surface area of a solid changes with dilation. When an object is dilated by a scale factor \( k \), the surface area of the object changes by a factor of \( k^2 \).

Here, the original surface area of the cylinder is given as \( 42\pi \) cm², and the scale factor is \( \frac{1}{2} \).

  1. Calculate the square of the scale factor:

\[ k^2 = \left(\frac{1}{2}\right)^2 = \frac{1}{4} \]

  1. Now, multiply the original surface area by this factor:

\[ \text{New Surface Area} = \text{Original Surface Area} \times k^2 = 42\pi \times \frac{1}{4} \]

\[ \text{New Surface Area} = \frac{42\pi}{4} = 10.5\pi , \text{cm}^2 \]

Thus, the surface area of the new cylinder after dilation is \( 10.5\pi , \text{cm}^2 \).

The correct answer is 10.5π cm².