A) Suppose you dilate a triangle using the scale factor of

1
3
. The original side lengths of the
triangle measure 11,9 and 28 inches. What is the perimeter of the dilated triangle? (1 point)

1 answer

To find the perimeter of the dilated triangle using a scale factor of \( \frac{1}{3} \), you first need to dilate each side length of the original triangle.

The original side lengths of the triangle are:

  • 11 inches
  • 9 inches
  • 28 inches

Now, we apply the scale factor of \( \frac{1}{3} \) to each side length:

  1. Dilation of the first side: \[ 11 \times \frac{1}{3} = \frac{11}{3} \text{ inches} \]

  2. Dilation of the second side: \[ 9 \times \frac{1}{3} = 3 \text{ inches} \]

  3. Dilation of the third side: \[ 28 \times \frac{1}{3} = \frac{28}{3} \text{ inches} \]

Now, we calculate the perimeter of the dilated triangle by summing the dilated side lengths:

\[ \text{Perimeter} = \frac{11}{3} + 3 + \frac{28}{3} \]

Convert 3 into a fraction with the same denominator:

\[ 3 = \frac{9}{3} \]

Now, adding the fractions together:

\[ \text{Perimeter} = \frac{11}{3} + \frac{9}{3} + \frac{28}{3} = \frac{11 + 9 + 28}{3} = \frac{48}{3} = 16 \text{ inches} \]

Thus, the perimeter of the dilated triangle is \( \boxed{16} \) inches.