Question

A bag contains 1 blue, 2 green, and 3 red marbles, as shown.
1 blue marble, 2 green marbles, and 3 red marbles.

What is the probability of drawing a green marble out of the bag without looking?
StartFraction 1 over 6 EndFraction
One-fifth
One-third
One-half

Answer 1

To find the probability of drawing a green marble from the bag, first determine the total number of marbles.

The bag contains:
- 1 blue marble
- 2 green marbles
- 3 red marbles

Total number of marbles = 1 (blue) + 2 (green) + 3 (red) = 6 marbles.

Next, we consider the number of favorable outcomes for drawing a green marble, which is 2 (since there are 2 green marbles).

The probability \( P \) of drawing a green marble is given by the formula:

\[
P(\text{green}) = \frac{\text{Number of green marbles}}{\text{Total number of marbles}} = \frac{2}{6} = \frac{1}{3}
\]

Thus, the probability of drawing a green marble is \(\frac{1}{3}\).

Therefore, the correct answer is **One-third**.