Question

Change the equation from standard form to slope-intercept form by solving for y.

11x−8y=−48




Bill's work:

−8y=−11x−48


y=11/8x+6




Bud's work:

−8y=−11x−48


y=−11x+6

Answer 1

To convert the equation \( 11x - 8y = -48 \) from standard form to slope-intercept form, we solve for \( y \).

Starting with the original equation:

\[
11x - 8y = -48
\]

First, isolate the term involving \( y \):

\[
-8y = -11x - 48
\]

Now, divide every term by \(-8\) to solve for \( y \):

\[
y = \frac{-11x}{-8} + \frac{-48}{-8}
\]

Simplifying this gives:

\[
y = \frac{11}{8}x + 6
\]

So the correct form of the equation in slope-intercept form is:

\[
y = \frac{11}{8}x + 6
\]

Now, let's evaluate Bill's and Bud's work:

- Bill's work shows correctly:

\[
y = \frac{11}{8}x + 6
\]

- Bud's work incorrectly states:

\[
y = -11x + 6
\]

Thus, Bill's work is correct, while Bud's work contains a mistake.