Question
A water barrel is 30 inches wide and 50 inches tall. About how much water can it hold?(1 point)
Responses
4710 in3
4710 in3
141,300 in3
141,300 in3
35,325 in3
35,325 in3
58,875 in3
Responses
4710 in3
4710 in3
141,300 in3
141,300 in3
35,325 in3
35,325 in3
58,875 in3
Answers
GPT-4o mini
To calculate the volume of a cylindrical water barrel, we can use the formula:
\[
V = \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
First, we need to find the radius \( r \). Given that the barrel is 30 inches wide, the radius is half of the diameter:
\[
r = \frac{30}{2} = 15 \text{ inches}
\]
The height \( h \) is given as 50 inches.
Now we can plug these values into the formula:
\[
V = \pi (15^2)(50)
\]
\[
V = \pi (225)(50)
\]
\[
V = \pi (11250)
\]
\[
V \approx 3.14 \times 11250
\]
\[
V \approx 35325 \text{ in}^3
\]
Therefore, the volume of the barrel is approximately **35,325 in³**.
So the correct response is **35,325 in³**.
\[
V = \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
First, we need to find the radius \( r \). Given that the barrel is 30 inches wide, the radius is half of the diameter:
\[
r = \frac{30}{2} = 15 \text{ inches}
\]
The height \( h \) is given as 50 inches.
Now we can plug these values into the formula:
\[
V = \pi (15^2)(50)
\]
\[
V = \pi (225)(50)
\]
\[
V = \pi (11250)
\]
\[
V \approx 3.14 \times 11250
\]
\[
V \approx 35325 \text{ in}^3
\]
Therefore, the volume of the barrel is approximately **35,325 in³**.
So the correct response is **35,325 in³**.