Question

A cylindrical gasoline can is 12 in. wide and 15 in. tall. About how much gasoline can it hold? Use 3.14
for π
.(1 point)
_ in.^3

Answer 1

To find the volume of a cylindrical gasoline can, you can use the formula for the volume of a cylinder:

\[
V = \pi r^2 h
\]

where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height of the cylinder.

Given:
- The diameter of the can is 12 inches, so the radius \( r \) is half of the diameter:

\[
r = \frac{12}{2} = 6 \text{ in}
\]

- The height \( h \) of the can is 15 inches.

Now, substituting these values into the volume formula:

\[
V = 3.14 \times (6^2) \times 15
\]

Calculating \( 6^2 \):

\[
6^2 = 36
\]

Now substituting back into the volume formula:

\[
V = 3.14 \times 36 \times 15
\]

Calculating \( 36 \times 15 \):

\[
36 \times 15 = 540
\]

Now substituting this back into the equation for volume:

\[
V = 3.14 \times 540
\]

Now calculating \( 3.14 \times 540 \):

\[
V = 1695.6
\]

Thus, the volume of the cylindrical gasoline can is approximately:

\[
\boxed{1695.6} \text{ in}^3
\]