Question

The graph shows the elevation of a deep-sea diver in relation to minutes passed. Using any two points on the graph, what is the rate of change in the diver’s elevation? (1 point) feet per minute "A coordinate plane shows quadrant 4 with the x-axis, labeled as minutes, ranging from 0 to 6 in increments of 1 and y-axis, labeled as elevation in feet, ranging from 0 to negative 110 in decrements of 10. A ray with arrow at the bottom end points downward from the origin. The coordinates that it passes through are left parenthesis 0 comma 0 right parenthesis, left parenthesis 3 comma negative 60 right parenthesis, and left parenthesis 5 comma negative 100 right parenthesis. "/>

Answer 1

To find the rate of change in the diver's elevation using two points, we can use any two points from the graph provided. Let's use the points \((0, 0)\) and \((5, -100)\).

The formula for the rate of change (slope) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:

\[ \text{Rate of Change} = \frac{y_2 - y_1}{x_2 - x_1} \]

Plugging in the coordinates of the points:

• \((x_1, y_1) = (0, 0)\)
• \((x_2, y_2) = (5, -100)\)

We compute:

\[ \text{Rate of Change} = \frac{-100 - 0}{5 - 0} = \frac{-100}{5} = -20 \]

Thus, the rate of change in the diver’s elevation is \(-20\) feet per minute.