dy/dx= (2x-2xy)/(x^2+2y)

Find all points on the curve where x=2. Show there is a horizontal tangent to the curve at one of those points.

Similar Questions

Consider the curve y^2+xy+x^2=15. What is dy/dx?Find the two points on the curve where y equals 0 and show that the tangent
1. 0 answers
Can someone show how this question is solved.Consider the curve given by the equation 2y^3 + y^2 - y^5 = x^4 -2x^3 +x^2 Find all
1. 1 answer
dy/dx= (2x-2xy)/(x^2+2y)Find all points on the curve where x=2. Show there is a horizontal tangent to the curve at one of those
1. 0 answers
x^2-x^2y=y^2-1find all points on the curve where x=2. Show there is a horizontal tangent to the curve at one of the points.
1. 2 answers