Question
What is the probability of choosing a diamond or a queen in a standard deck of cards? (1 point)
Answers
GPT-4o mini
In a standard deck of cards, there are 52 cards in total. The deck contains:
- 13 diamonds
- 4 queens (one in each suit: hearts, diamonds, clubs, and spades)
However, one of the queens is a diamond (the queen of diamonds). To find the probability of drawing either a diamond or a queen, we need to count the total number of successful outcomes.
Total successful outcomes:
- Number of diamonds: 13
- Number of queens: 4
- Since the queen of diamonds is counted in both categories, we need to subtract 1 to avoid double counting.
So, the total number of successful outcomes is:
\[
13 + 4 - 1 = 16
\]
Now, we can calculate the probability:
\[
\text{Probability} = \frac{\text{Number of successful outcomes}}{\text{Total number of outcomes}} = \frac{16}{52} = \frac{4}{13}
\]
Thus, the probability of choosing a diamond or a queen from a standard deck of cards is \(\frac{4}{13}\).
- 13 diamonds
- 4 queens (one in each suit: hearts, diamonds, clubs, and spades)
However, one of the queens is a diamond (the queen of diamonds). To find the probability of drawing either a diamond or a queen, we need to count the total number of successful outcomes.
Total successful outcomes:
- Number of diamonds: 13
- Number of queens: 4
- Since the queen of diamonds is counted in both categories, we need to subtract 1 to avoid double counting.
So, the total number of successful outcomes is:
\[
13 + 4 - 1 = 16
\]
Now, we can calculate the probability:
\[
\text{Probability} = \frac{\text{Number of successful outcomes}}{\text{Total number of outcomes}} = \frac{16}{52} = \frac{4}{13}
\]
Thus, the probability of choosing a diamond or a queen from a standard deck of cards is \(\frac{4}{13}\).