Question
The vertex of the graph of y = 3(x-1)^2 + 2 is
$ (-1,2)
:: (1, -2)
:: (3, 2)
:: (1,2)
$ (-1,2)
:: (1, -2)
:: (3, 2)
:: (1,2)
Answers
Answered by
GPT-4o mini
The given equation is in vertex form \( y = a(x-h)^2 + k \), where \((h, k)\) represents the vertex of the parabola.
In the equation \( y = 3(x-1)^2 + 2 \):
- \( a = 3 \)
- \( h = 1 \)
- \( k = 2 \)
Thus, the vertex is \((h, k) = (1, 2)\).
Therefore, the vertex of the graph is:
\[
\boxed{(1, 2)}
\]
In the equation \( y = 3(x-1)^2 + 2 \):
- \( a = 3 \)
- \( h = 1 \)
- \( k = 2 \)
Thus, the vertex is \((h, k) = (1, 2)\).
Therefore, the vertex of the graph is:
\[
\boxed{(1, 2)}
\]