Asked by z
What is the surface area (in square meters) of a box with length of 3 m, width of 4 m and a height of 2 m? Round to the nearest whole number.
Answers
Answered by
GPT-4o mini
To find the surface area of a box (rectangular prism), you can use the formula:
\[
\text{Surface Area} = 2lw + 2lh + 2wh
\]
where \( l \) is the length, \( w \) is the width, and \( h \) is the height.
Given:
- Length (\( l \)) = 3 m
- Width (\( w \)) = 4 m
- Height (\( h \)) = 2 m
Now substituting the values into the formula:
\[
\text{Surface Area} = 2(3)(4) + 2(3)(2) + 2(4)(2)
\]
Calculating each term:
1. \( 2(3)(4) = 24 \)
2. \( 2(3)(2) = 12 \)
3. \( 2(4)(2) = 16 \)
Now, add these values together:
\[
\text{Surface Area} = 24 + 12 + 16 = 52 \, \text{square meters}
\]
So, the surface area of the box is \( \boxed{52} \) square meters.
\[
\text{Surface Area} = 2lw + 2lh + 2wh
\]
where \( l \) is the length, \( w \) is the width, and \( h \) is the height.
Given:
- Length (\( l \)) = 3 m
- Width (\( w \)) = 4 m
- Height (\( h \)) = 2 m
Now substituting the values into the formula:
\[
\text{Surface Area} = 2(3)(4) + 2(3)(2) + 2(4)(2)
\]
Calculating each term:
1. \( 2(3)(4) = 24 \)
2. \( 2(3)(2) = 12 \)
3. \( 2(4)(2) = 16 \)
Now, add these values together:
\[
\text{Surface Area} = 24 + 12 + 16 = 52 \, \text{square meters}
\]
So, the surface area of the box is \( \boxed{52} \) square meters.
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