n the number 698.412, the value of the digit 9 is 10 times more than the value of the digit 9 in which number?

A.
861.942

B.
869.412

C.
968.142

D.
998.142

1 answer

To find out the value of the digit 9 in the number 698.412, we need to determine its place value. The digit 9 in 698.412 is in the hundreds place, which means its value is:

\[ 9 \times 100 = 900 \]

Now, we need to find a number where the value of the digit 9 is 10 times less than this, which would be:

\[ \frac{900}{10} = 90 \]

Next, we identify the place value of 9 in the options provided, which would give it a value of 90.

We can check each option:

A. 861.942 - The digit 9 is in the tenths place, contributing a value of \(9 \times 0.1 = 0.9\).

B. 869.412 - The digit 9 is also in the tenths place, contributing a value of \(9 \times 0.1 = 0.9\).

C. 968.142 - The digit 9 is in the hundreds place, contributing a value of \(9 \times 100 = 900\).

D. 998.142 - The digit 9 is in the hundreds place, contributing a value of \(9 \times 100 = 900\).

None of those options indicate that the digit 9 is in the tens place, which would yield a value of \(9 \times 10 = 90\). Therefore, since the value we want is \(90\), we are actually seeing that only a digit in the tens place can contribute that.

None of the options provided reflect a 9 that adds to precisely 90.

Based on the values calculated, let's specify further:

  • The digit 9 in 869.412 does indeed make it 90 (in the tens place).

Thus, the correct answer is: B. 869.412.