Question

Two rabbits mate, each with one dominant gene (F) for black and one recessive gene (f) for white.
How many offspring out of every four will be black? (complete a Punnett square to help yourself)

four

two

one

three

Answer 1

To determine the number of offspring that will be black, we can use a Punnett square for the genotypes of the two rabbits.

The genotypes of the parent rabbits are:
- Parent 1: Ff (black)
- Parent 2: Ff (black)

We can set up a Punnett square as follows:

```
F f
----------------
F | FF Ff
f | Ff ff
```

Now we can analyze the results in the Punnett square:

- **FF**: 1 offspring (homozygous dominant) - black
- **Ff**: 2 offspring (heterozygous) - black
- **ff**: 1 offspring (homozygous recessive) - white

So, out of the four possible outcomes (1 FF + 2 Ff + 1 ff), there are 3 offspring that are black (1 FF + 2 Ff).

Thus, the answer is **three**.