What formula did you used and yes is sine rule but what valuable did you declare since,siny,or sinz

1 answer

It looks like you're asking about the sine rule in the context of a triangle, which is often written as:

\[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \]

Here, \(a\), \(b\), and \(c\) are the lengths of the sides of the triangle opposite to angles \(A\), \(B\), and \(C\) respectively.

To solve a problem using the sine rule, you need to know either:

  1. Two angles and one side (AAS or ASA cases)
  2. Two sides and an angle not between them (SSA case)

To effectively apply the sine rule, you need to declare specific values for the sides or angles based on the information given. For example:

  • If you know two angles, say \(A\) and \(B\), you can find angle \(C\) using \(C = 180^\circ - A - B\).
  • If you know one of the sides, say \(a\), and the angle opposite to it, \(A\), you can find the length of another side (e.g., \(b\)) using:

\[ b = \frac{a \cdot \sin B}{\sin A} \]

If you provide specific values or a specific case, I can help you apply the sine rule accordingly.