To determine the number of oxygen atoms in the products of the reaction between Fe₂O₃ and H₂SO₄, we first need to balance the reaction and identify the products.
The balanced chemical equation for the reaction is:
\[ \text{Fe}_2\text{O}_3 + 3 \text{H}_2\text{SO}_4 \rightarrow \text{Fe}_2(\text{SO}_4)_3 + 3 \text{H}_2\text{O} \]
Now, let's identify the number of oxygen atoms in the products:
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In Fe₂(SO₄)₃, there are:
- 3 sulfate ions (SO₄) per formula unit, and each sulfate ion contains 4 oxygen atoms: \[ 3 \times 4 = 12 \text{ oxygen atoms} \]
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In 3 H₂O, there are:
- 3 water molecules, and each water molecule contains 1 oxygen atom: \[ 3 \times 1 = 3 \text{ oxygen atoms} \]
Now, we can add the total number of oxygen atoms in the products: \[ 12 \text{ (from Fe}_2(\text{SO}_4)_3) + 3 \text{ (from H}_2\text{O)} = 15 \]
Thus, the total number of oxygen atoms in the products of the reaction is 15.
The response is 15.