Question
Edgar accumulated 5,000
in credit card debt. If the interest rate is 20% owe on this debt in 2 years by each method of compounding? Round your answer to the nearest cent with no commas or dollar signs. Compound quarterly
7387.28
7237.12
7459.12
7434.57
in credit card debt. If the interest rate is 20% owe on this debt in 2 years by each method of compounding? Round your answer to the nearest cent with no commas or dollar signs. Compound quarterly
7387.28
7237.12
7459.12
7434.57
Answers
Answered by
GPT-4o mini
To calculate the amount owed after 2 years with compound interest compounded quarterly, we can use the formula:
\[
A = P \left(1 + \frac{r}{n}\right)^{nt}
\]
where:
- \( A \) is the amount owed after time \( t \),
- \( P \) is the principal amount (initial debt),
- \( r \) is the annual interest rate (decimal),
- \( n \) is the number of times interest is compounded per year,
- \( t \) is the time in years.
Given:
- \( P = 5000 \)
- \( r = 0.20 \) (20%)
- \( n = 4 \) (quarterly)
- \( t = 2 \)
Now, substituting the values into the formula:
\[
A = 5000 \left(1 + \frac{0.20}{4}\right)^{4 \times 2}
\]
Calculating:
1. Calculate \(\frac{0.20}{4}\):
\[
\frac{0.20}{4} = 0.05
\]
2. Substitute back into the formula:
\[
A = 5000 \left(1 + 0.05\right)^{8}
\]
3. Calculate \(1 + 0.05\):
\[
1 + 0.05 = 1.05
\]
4. Now we find \(A\):
\[
A = 5000 \left(1.05\right)^{8}
\]
Calculating \(1.05^8\):
\[
1.05^8 \approx 1.477455
\]
5. Now multiply by the principal:
\[
A \approx 5000 \times 1.477455 \approx 7387.28
\]
Therefore, the total amount owed after 2 years, compounded quarterly, is **7387.28**.
\[
A = P \left(1 + \frac{r}{n}\right)^{nt}
\]
where:
- \( A \) is the amount owed after time \( t \),
- \( P \) is the principal amount (initial debt),
- \( r \) is the annual interest rate (decimal),
- \( n \) is the number of times interest is compounded per year,
- \( t \) is the time in years.
Given:
- \( P = 5000 \)
- \( r = 0.20 \) (20%)
- \( n = 4 \) (quarterly)
- \( t = 2 \)
Now, substituting the values into the formula:
\[
A = 5000 \left(1 + \frac{0.20}{4}\right)^{4 \times 2}
\]
Calculating:
1. Calculate \(\frac{0.20}{4}\):
\[
\frac{0.20}{4} = 0.05
\]
2. Substitute back into the formula:
\[
A = 5000 \left(1 + 0.05\right)^{8}
\]
3. Calculate \(1 + 0.05\):
\[
1 + 0.05 = 1.05
\]
4. Now we find \(A\):
\[
A = 5000 \left(1.05\right)^{8}
\]
Calculating \(1.05^8\):
\[
1.05^8 \approx 1.477455
\]
5. Now multiply by the principal:
\[
A \approx 5000 \times 1.477455 \approx 7387.28
\]
Therefore, the total amount owed after 2 years, compounded quarterly, is **7387.28**.