Question
In 1985, there were 285 cell phone subscribers in a small town. The number of subscribers increases by 75% each year until 1994. How many subscribers are there in the year 1994? (HINT: how many years is it from 1985 to 1994?)
Answers
GPT-4o mini
The number of years from 1985 to 1994 is 9 years.
To calculate the number of subscribers in 1994, we can use the formula for exponential growth. Since the number of subscribers increases by 75% each year, we can express this growth as follows:
\[
N(t) = N_0 \times (1 + r)^t
\]
Where:
- \( N(t) \) is the number of subscribers at time \( t \),
- \( N_0 \) is the initial number of subscribers (285),
- \( r \) is the growth rate (75% or 0.75),
- \( t \) is the number of years (9).
Plugging in the values:
\[
N(9) = 285 \times (1 + 0.75)^9
\]
Calculating \( (1 + 0.75) \):
\[
1 + 0.75 = 1.75
\]
Now raise 1.75 to the power of 9:
\[
1.75^9 \approx 33.4132
\]
Now multiply by the initial number of subscribers:
\[
N(9) = 285 \times 33.4132 \approx 9512.282
\]
Rounding to the nearest whole number, the estimated number of subscribers in 1994 is approximately:
\[
\boxed{9512}
\]
To calculate the number of subscribers in 1994, we can use the formula for exponential growth. Since the number of subscribers increases by 75% each year, we can express this growth as follows:
\[
N(t) = N_0 \times (1 + r)^t
\]
Where:
- \( N(t) \) is the number of subscribers at time \( t \),
- \( N_0 \) is the initial number of subscribers (285),
- \( r \) is the growth rate (75% or 0.75),
- \( t \) is the number of years (9).
Plugging in the values:
\[
N(9) = 285 \times (1 + 0.75)^9
\]
Calculating \( (1 + 0.75) \):
\[
1 + 0.75 = 1.75
\]
Now raise 1.75 to the power of 9:
\[
1.75^9 \approx 33.4132
\]
Now multiply by the initial number of subscribers:
\[
N(9) = 285 \times 33.4132 \approx 9512.282
\]
Rounding to the nearest whole number, the estimated number of subscribers in 1994 is approximately:
\[
\boxed{9512}
\]