Asked by Anonymous
A ball is dropped from the same height, but 20
feet away from the side of the building. The height y of the
ball at time t is given by y(t) = 64 − 16t2. How fast is the
shadow of the ball moving along the ground after 1 second?
feet away from the side of the building. The height y of the
ball at time t is given by y(t) = 64 − 16t2. How fast is the
shadow of the ball moving along the ground after 1 second?
Answers
Answered by
MathMate
The velocity of the ball after time t is given by:
y'(t)=-32t
The shadow cannot be traced unless the position of the sun or light source is known.
y'(t)=-32t
The shadow cannot be traced unless the position of the sun or light source is known.
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