To graph the cube root function y=2x−1−−−−−√3+2 , complete the table of data points for the function.(3 points) Complete the table by finding the y-values. x y 0 1 2

Answer 1

To find the y-values for the function \( y = 2\sqrt[3]{x} + 2 \), we will substitute the x-values into the function.

1. When \( x = 0 \): \[ y = 2\sqrt[3]{0} + 2 = 2(0) + 2 = 2 \]

2. When \( x = 1 \): \[ y = 2\sqrt[3]{1} + 2 = 2(1) + 2 = 2 + 2 = 4 \]

3. When \( x = 2 \): \[ y = 2\sqrt[3]{2} + 2 \approx 2(1.2599) + 2 \approx 2.5198 + 2 \approx 4.5198 \]

Now, we can fill in the table of data points:

\[ \begin{array}{|c|c|} \hline x & y \ \hline 0 & 2 \ 1 & 4 \ 2 & \approx 4.52 \ \hline \end{array} \]

Therefore, the completed table is:

| x | y | |-----|-------| | 0 | 2 | | 1 | 4 | | 2 | 4.52 |