Asked by bill
Round any decimals to the nearest penny. You save $3,260.00 in a savings account earning 3.55% APR compounded monthly.
How much is the total interest earned by the end of the third month?
How much is the total interest earned by the end of the third month?
Answers
Answered by
GPT-4o mini
To calculate the total interest earned by the end of the third month in a savings account with an APR of 3.55% compounded monthly, we can use the compound interest formula:
\[
A = P \left(1 + \frac{r}{n}\right)^{nt}
\]
Where:
- \(A\) is the amount of money accumulated after n years, including interest.
- \(P\) is the principal amount (the initial amount of money).
- \(r\) is the annual interest rate (decimal).
- \(n\) is the number of times that interest is compounded per year.
- \(t\) is the time the money is invested or borrowed for in years.
Given:
- \(P = 3260.00\)
- \(r = 3.55\% = 0.0355\)
- \(n = 12\) (since it's compounded monthly)
- \(t = \frac{3}{12} = 0.25\) years (for 3 months)
Now, substituting these values into the formula:
\[
A = 3260 \left(1 + \frac{0.0355}{12}\right)^{12 \cdot 0.25}
\]
Calculating \(\frac{0.0355}{12}\):
\[
\frac{0.0355}{12} \approx 0.00295833
\]
Now calculate \(A\):
\[
A = 3260 \left(1 + 0.00295833\right)^{3}
\]
Calculating \((1 + 0.00295833)^3\):
\[
(1.00295833)^3 \approx 1.008895
\]
Now, substituting this back into the formula for \(A\):
\[
A \approx 3260 \times 1.008895 \approx 3284.06
\]
Now, to find the interest earned, subtract the initial principal from the total amount:
\[
\text{Interest} = A - P = 3284.06 - 3260.00 = 24.06
\]
Thus, the total interest earned by the end of the third month, rounded to the nearest penny, is **$24.06**.
\[
A = P \left(1 + \frac{r}{n}\right)^{nt}
\]
Where:
- \(A\) is the amount of money accumulated after n years, including interest.
- \(P\) is the principal amount (the initial amount of money).
- \(r\) is the annual interest rate (decimal).
- \(n\) is the number of times that interest is compounded per year.
- \(t\) is the time the money is invested or borrowed for in years.
Given:
- \(P = 3260.00\)
- \(r = 3.55\% = 0.0355\)
- \(n = 12\) (since it's compounded monthly)
- \(t = \frac{3}{12} = 0.25\) years (for 3 months)
Now, substituting these values into the formula:
\[
A = 3260 \left(1 + \frac{0.0355}{12}\right)^{12 \cdot 0.25}
\]
Calculating \(\frac{0.0355}{12}\):
\[
\frac{0.0355}{12} \approx 0.00295833
\]
Now calculate \(A\):
\[
A = 3260 \left(1 + 0.00295833\right)^{3}
\]
Calculating \((1 + 0.00295833)^3\):
\[
(1.00295833)^3 \approx 1.008895
\]
Now, substituting this back into the formula for \(A\):
\[
A \approx 3260 \times 1.008895 \approx 3284.06
\]
Now, to find the interest earned, subtract the initial principal from the total amount:
\[
\text{Interest} = A - P = 3284.06 - 3260.00 = 24.06
\]
Thus, the total interest earned by the end of the third month, rounded to the nearest penny, is **$24.06**.
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