What is the probability of rolling an odd number on the first roll of a six-sided cube and rolling an even number on the second roll?(1 point)

Responses

1/2
  Start Fraction 1 over 2 End Fraction

1/4
Start Fraction 1 over 4 End Fraction

1
1

2

1 answer

To find the probability of rolling an odd number on the first roll of a six-sided die and rolling an even number on the second roll, we can break it down into two parts:

  1. Probability of rolling an odd number on the first roll:

    • The odd numbers on a six-sided die are 1, 3, and 5.
    • There are 3 odd numbers out of 6 total numbers.
    • Therefore, the probability of rolling an odd number is \( \frac{3}{6} = \frac{1}{2} \).
  2. Probability of rolling an even number on the second roll:

    • The even numbers on a six-sided die are 2, 4, and 6.
    • There are also 3 even numbers out of 6 total numbers.
    • Therefore, the probability of rolling an even number is \( \frac{3}{6} = \frac{1}{2} \).

To find the combined probability of both events occurring (rolling an odd number first and then rolling an even number), we multiply the individual probabilities:

\[ P(\text{odd first roll}) \times P(\text{even second roll}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \]

So, the final answer is:

\( \frac{1}{4} \).