Asked by idk the answer
Change the equation y=
5
6
x+7 to standard form.
6x−5y=−35
6x+5y=−35
5x−6y=7
6x+5y=7
5
6
x+7 to standard form.
6x−5y=−35
6x+5y=−35
5x−6y=7
6x+5y=7
Answers
Answered by
GPT-4o mini
To convert the equation \( y = \frac{5}{6} x + 7 \) to standard form, we want to rearrange it into the form \( Ax + By = C \), where \( A \), \( B \), and \( C \) are integers.
Starting with the equation:
\[ y = \frac{5}{6}x + 7 \]
1. First, eliminate the fraction by multiplying every term by 6:
\[ 6y = 5x + 42 \]
2. Next, rearrange it into standard form:
\[ -5x + 6y = 42 \]
To make the \( x \) coefficient positive, we can multiply the whole equation by -1:
\[ 5x - 6y = -42 \]
Therefore, the equation in standard form is:
**\( 5x - 6y = -42 \)**
However, noting the options provided, the closest option available is **\( 5x - 6y = 7 \)**, which is not the correct transformation of the original equation.
If you're looking for the form most closely resembling standard forms provided in your options, then **none of them appear to match directly**, but standard versus modified might offer a contextual fit.
Correct integer conversion remains **\( 5x - 6y = -42 \)** upon correctly interpreting from the starting expression without completing shifts.
Starting with the equation:
\[ y = \frac{5}{6}x + 7 \]
1. First, eliminate the fraction by multiplying every term by 6:
\[ 6y = 5x + 42 \]
2. Next, rearrange it into standard form:
\[ -5x + 6y = 42 \]
To make the \( x \) coefficient positive, we can multiply the whole equation by -1:
\[ 5x - 6y = -42 \]
Therefore, the equation in standard form is:
**\( 5x - 6y = -42 \)**
However, noting the options provided, the closest option available is **\( 5x - 6y = 7 \)**, which is not the correct transformation of the original equation.
If you're looking for the form most closely resembling standard forms provided in your options, then **none of them appear to match directly**, but standard versus modified might offer a contextual fit.
Correct integer conversion remains **\( 5x - 6y = -42 \)** upon correctly interpreting from the starting expression without completing shifts.