Willow is in her fourth year working for the same company. Her starting salary was $48,000. The next year, her salary was $50,400. The following year, her salary was $52,920. This year, her salary is $55,566. Willow’s boss says her salary will continue to increase by the same percentage each year. (4 points) Write the values given in the scenario as a sequence. Do not use $ in the answers. , , , Question 2 Select the appropriate answer.(1 point) This is an example of sequence. Question 3 Create a function that models this sequence/scenario. (3 points) S(n)= ()n By what percentage is Willow’s salary increasing each year?

1 answer

Let's break down the assignment step by step.

Question 1: Write the values given in the scenario as a sequence.

The salaries over the four years can be written as a sequence:

Sequence:
48000, 50400, 52920, 55566

Question 2: Select the appropriate answer.

This is an example of a geometric sequence because Willow's salary increases by a constant percentage each year.

Question 3: Create a function that models this sequence/scenario.

To model the sequence using a function, we can determine the common ratio (the percentage increase) first. We can calculate the percentage increase year over year.

  1. Calculate the percentage increase between the years:

    • From $48,000 to $50,400: \[ \text{Percentage Increase} = \left(\frac{50400 - 48000}{48000}\right) \times 100 = \left(\frac{2400}{48000}\right) \times 100 = 5% \]

    • From $50,400 to $52,920: \[ \text{Percentage Increase} = \left(\frac{52920 - 50400}{50400}\right) \times 100 = \left(\frac{2520}{50400}\right) \times 100 = 5% \]

    • From $52,920 to $55,566: \[ \text{Percentage Increase} = \left(\frac{55566 - 52920}{52920}\right) \times 100 = \left(\frac{2646}{52920}\right) \times 100 = 5% \]

The percentage increase each year is consistently 5%.

Now that we know the percentage increase is 5%, we can create the function.

The formula for a geometric sequence can be given by: \[ S(n) = a \cdot r^{(n - 1)} \] where:

  • \( S(n) \) is the salary in the nth year,
  • \( a \) is the initial salary ($48,000),
  • \( r \) is the common ratio (1 + percentage increase as a decimal; for 5%, it is 1.05),
  • \( n \) is the year number.

Thus, the function modeling Willow's salary sequence would be:

Function:
\[ S(n) = 48000 \cdot (1.05)^{(n - 1)} \]

Summary of Answers:

  1. Sequence: 48000, 50400, 52920, 55566
  2. Type of sequence: Geometric sequence
  3. Function: S(n) = 48000 * (1.05)^{(n - 1)}
  4. Percentage increase: 5%