Question
The predicted ticket sales for the opening weekend of two new movies are 1.8×107
tickets for movie Y and 4.5×106
tickets for movie Z. According to this prediction, how many more tickets will be sold for movie Y than for movie Z?
A.
2.5 times as many
B.
4 times as many
C.
0.4 times as many
D.
0.25 times as many
tickets for movie Y and 4.5×106
tickets for movie Z. According to this prediction, how many more tickets will be sold for movie Y than for movie Z?
A.
2.5 times as many
B.
4 times as many
C.
0.4 times as many
D.
0.25 times as many
Answers
GPT-4o mini
To find out how many more tickets will be sold for movie Y than for movie Z, we need to subtract the predicted ticket sales of movie Z from those of movie Y.
Given:
- Movie Y: \( 1.8 \times 10^7 \) tickets
- Movie Z: \( 4.5 \times 10^6 \) tickets
First, we convert both numbers to the same power of ten to simplify the subtraction:
- Movie Z: \( 4.5 \times 10^6 = 0.45 \times 10^7 \) (by moving the decimal point one place to the left)
Now, we can perform the subtraction:
\[
1.8 \times 10^7 - 0.45 \times 10^7 = (1.8 - 0.45) \times 10^7 = 1.35 \times 10^7
\]
This means movie Y is predicted to sell \( 1.35 \times 10^7 \) more tickets than movie Z.
Now let's determine how many times more this is compared to movie Z's sales:
To find the factor, we can divide the difference by the sales of movie Z:
\[
\text{Factor} = \frac{1.35 \times 10^7}{4.5 \times 10^6}
\]
Calculating this:
\[
= \frac{1.35}{4.5} \times \frac{10^7}{10^6} = \frac{1.35}{4.5} \times 10^{1}
= 0.3 \times 10^{1} = 3
\]
Thus, movie Y is predicted to sell 3 times as many tickets as movie Z.
The correct answer format does not match with the options directly. But seeing the options provided:
- A. 2.5 times as many
- B. 4 times as many
- C. 0.4 times as many
- D. 0.25 times as many
None of the options account for "3 times as many," so please verify if there are any changes in options or additional instructions. Otherwise, the answer indicates that movie Y is predicted to sell **3 times** as many tickets compared to movie Z.
Given:
- Movie Y: \( 1.8 \times 10^7 \) tickets
- Movie Z: \( 4.5 \times 10^6 \) tickets
First, we convert both numbers to the same power of ten to simplify the subtraction:
- Movie Z: \( 4.5 \times 10^6 = 0.45 \times 10^7 \) (by moving the decimal point one place to the left)
Now, we can perform the subtraction:
\[
1.8 \times 10^7 - 0.45 \times 10^7 = (1.8 - 0.45) \times 10^7 = 1.35 \times 10^7
\]
This means movie Y is predicted to sell \( 1.35 \times 10^7 \) more tickets than movie Z.
Now let's determine how many times more this is compared to movie Z's sales:
To find the factor, we can divide the difference by the sales of movie Z:
\[
\text{Factor} = \frac{1.35 \times 10^7}{4.5 \times 10^6}
\]
Calculating this:
\[
= \frac{1.35}{4.5} \times \frac{10^7}{10^6} = \frac{1.35}{4.5} \times 10^{1}
= 0.3 \times 10^{1} = 3
\]
Thus, movie Y is predicted to sell 3 times as many tickets as movie Z.
The correct answer format does not match with the options directly. But seeing the options provided:
- A. 2.5 times as many
- B. 4 times as many
- C. 0.4 times as many
- D. 0.25 times as many
None of the options account for "3 times as many," so please verify if there are any changes in options or additional instructions. Otherwise, the answer indicates that movie Y is predicted to sell **3 times** as many tickets compared to movie Z.