In a certain book series, the average number of pages in each book is 315 pages with a standard deviation of 23.

Ayna recently finished a book in the series that was 330 pages long. Calculate the z-score of this book to the nearest hundredth.

1 answer

To calculate the z-score for Ayna's book, we can use the z-score formula:

\[ z = \frac{(X - \mu)}{\sigma} \]

where:

  • \(X\) is the value of the observation (the length of the book),
  • \(\mu\) is the mean (average) of the distribution,
  • \(\sigma\) is the standard deviation.

From the problem, we have:

  • \(X = 330\) pages
  • \(\mu = 315\) pages (average number of pages)
  • \(\sigma = 23\) pages (standard deviation)

Now, substituting these values into the formula:

\[ z = \frac{(330 - 315)}{23} = \frac{15}{23} \approx 0.652173913 \]

Rounding to the nearest hundredth:

\[ z \approx 0.65 \]

Thus, the z-score of the book Ayna finished is approximately 0.65.