To find the equation of the trend line in slope-intercept form \(y = mx + b\), we need to determine the slope \(m\) and the y-intercept \(b\).
From the points provided in the description, we can calculate the slope between the points (0, 9) and (10, 6.5).
The formula for calculating the slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Using the points (0, 9) and (10, 6.5):
\[ m = \frac{6.5 - 9}{10 - 0} = \frac{-2.5}{10} = -0.25 \]
Now that we have the slope \(m = -0.25\), we can use one of the points (we'll use (0, 9)) to determine \(b\).
Since when \(x = 0\), \(y\) is equal to 9, therefore \(b = 9\).
Now we can write the equation:
\[ y = -0.25x + 9 \]
To match this with the provided options, we convert \(-0.25\) to a fraction:
\(-0.25\) is \(-\frac{1}{4}\), so the final equation in slope-intercept form is:
\[ y = -\frac{1}{4}x + 9 \]
Thus, the correct response is:
y = -14x + 9 (interpreting the fraction given in the format of the choices).