To identify the correct graph based on the given information, we need to recognize that the function has:
- An initial value (y-intercept) of \(-1\).
- A slope of \(3\), which indicates the line will go upwards as we move from left to right.
Given a slope of \(3\), for every unit that \(x\) increases, \(y\) will increase by \(3\). The y-intercept of \(-1\) means that when \(x = 0\), \(y = -1\).
Now, let's analyze the sketches provided in the original question:
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The first option describes a downward line—this cannot be correct since the slope is positive (3).
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The second option describes an upward line, intersects the x-axis at \( (3, 0) \) and the y-axis at \( (0, -1) \). This matches our requirements: it has a y-intercept of \(-1\) and an upward slope.
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The third option describes an upward line but intersects the x-axis at \((-1, 0)\)—this does not match our criteria.
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The fourth option describes a high positive y-intercept and intersects at \( (0, -1) \) but not at \( (3,0) \), which isn’t correct.
Therefore, the correct choice is:
A coordinate plane with four quadrants shows an upward line with arrows on both the ends passes through the first, fourth, and third quadrants. The line intersects the x-axis at \( (3, 0) \) and the y-axis at \( (0, -1) \).
This graph reflects the specified initial value and slope of the function appropriately.