Asked by Val
A stone thrown off a bridge 20 m above a river has an initial velocity of 12 m/s at an angle of 450 above the horizontal.
a. What is the range of the stone?
b. At what velocity does the stone strike the water?
(magnitude and direction)
a. What is the range of the stone?
b. At what velocity does the stone strike the water?
(magnitude and direction)
Answers
Answered by
bobpursley
break the initial velocity into horizontal and vertical components.
In the vertical:
-20=0+Vvi*t-4.9t^2
solve for t.
Range: Vhi*t
In the vertical:
-20=0+Vvi*t-4.9t^2
solve for t.
Range: Vhi*t
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