It looks like there is a misunderstanding with the formatting of the equation, as it appears to have two equal signs, which is not standard in algebra. Let's break it down and simplify the equation step by step.
The original equation you provided seems to be:
\[ 3(x + 4) + 5x = 4(x - 3) \]
Let's solve this equation step-by-step.
-
Distribute the terms: \[ 3(x + 4) = 3x + 12 \] \[ 4(x - 3) = 4x - 12 \]
Now substitute these back into the equation: \[ 3x + 12 + 5x = 4x - 12 \]
-
Combine like terms on the left side: \[ (3x + 5x) + 12 = 4x - 12 \] \[ 8x + 12 = 4x - 12 \]
-
Rearrange the equation to isolate the variable \(x\): \[ 8x - 4x + 12 = -12 \] \[ 4x + 12 = -12 \] \[ 4x = -12 - 12 \] \[ 4x = -24 \]
-
Solve for \(x\): \[ x = \frac{-24}{4} = -6 \]
Thus, the solution to the equation \( 3(x + 4) + 5x = 4(x - 3) \) is:
\[ \boxed{-6} \]
If you meant something different with the second equal sign \(= 8x\), please clarify and I can help you with that!