In circle D with m, angle, C, D, E, equals, 144, degreesm∠CDE=144


and C, D, equals, 4CD=4, find the area of sector CDE. Round to the nearest hundredth.

1 answer

To find the area of sector \( CDE \) in circle \( D \), we need to use the formula for the area of a sector:

\[ \text{Area of the sector} = \frac{\theta}{360} \times \pi r^2 \]

where \( \theta \) is the central angle in degrees and \( r \) is the radius of the circle.

  1. Identify the values:

    • Given \( m\angle CDE = 144^\circ \)
    • The distance \( CD = 4 \). This is the radius \( r \) of the circle, so \( r = 4 \).
  2. Plug the values into the formula: \[ \text{Area of the sector} = \frac{144}{360} \times \pi (4^2) \]

  3. Calculate \( r^2 \): \[ 4^2 = 16 \]

  4. Calculate the fraction: \[ \frac{144}{360} = \frac{2}{5} \text{ (simplifying 144 and 360)} \]

  5. Substituting the values: \[ \text{Area of the sector} = \frac{2}{5} \times \pi \times 16 \] \[ = \frac{32\pi}{5} \]

  6. Calculate this value: \[ \text{Area of the sector} \approx \frac{32 \times 3.14159}{5} \approx \frac{100.53088}{5} \approx 20.106176 \]

  7. Round to the nearest hundredth: \[ \text{Area of the sector} \approx 20.11 \]

Thus, the area of sector \( CDE \) is approximately 20.11 square units.