In circle Q with m, angle, P, Q, R, equals, 86, degreesm∠PQR=86


and P, Q, equals, 10PQ=10, find the area of sector PQR. Round to the nearest hundredth.

1 answer

To find the area of sector \( PQR \) in circle \( Q \), we will use the formula for the area of a sector:

\[ \text{Area of sector} = \frac{m\angle PQR}{360^\circ} \times \pi r^2 \]

Where:

  • \( m\angle PQR \) is the measure of the angle in degrees.
  • \( r \) is the radius of the circle.

Given:

  • \( m\angle PQR = 86^\circ \)
  • \( PQ = 10 \), which is the radius \( r \) of the circle.

Now substituting the values into the area formula:

\[ \text{Area of sector} = \frac{86}{360} \times \pi \times 10^2 \]

Calculating step-by-step:

  1. Calculate \( \frac{86}{360} \):

\[ \frac{86}{360} \approx 0.2389 \]

  1. Calculate \( 10^2 \):

\[ 10^2 = 100 \]

  1. The area calculation becomes:

\[ \text{Area of sector} \approx 0.2389 \times \pi \times 100 \]

  1. Using \( \pi \approx 3.1416 \):

\[ \text{Area of sector} \approx 0.2389 \times 3.1416 \times 100 \]

  1. Calculate \( 0.2389 \times 3.1416 \):

\[ 0.2389 \times 3.1416 \approx 0.7505 \]

  1. Finally, multiply by 100:

\[ \text{Area of sector} \approx 0.7505 \times 100 = 75.05 \]

Thus, rounding to the nearest hundredth, the area of sector \( PQR \) is approximately:

\[ \boxed{75.05} \]