In circle G with m, angle, F, G, H, equals, 60, degreesm∠FGH=60∘

and F, G, equals, 5FG=5, find the area of sector FGH. Round to the nearest hundredth.

1 answer

To find the area of sector FGH in circle G, we need to use the formula for the area of a sector:

\[ \text{Area of sector} = \frac{m\angle \text{FGH}}{360^\circ} \times \pi r^2 \]

Where:

  • \( m\angle FGH = 60^\circ \) (given)
  • \( r = FG = 5 \) (given as the radius)

Now we can substitute the values into the formula.

  1. First, calculate \( \pi r^2 \):

\[ r = 5 \implies r^2 = 5^2 = 25 \]

\[ \pi r^2 = \pi \times 25 \approx 78.54 \quad (\text{using } \pi \approx 3.14) \]

  1. Now plug this into the area formula:

\[ \text{Area of sector} = \frac{60}{360} \times \pi r^2 = \frac{1}{6} \times 78.54 \]

  1. Calculate the fraction:

\[ \frac{1}{6} \times 78.54 \approx 13.09 \]

Therefore, the area of sector FGH, rounded to the nearest hundredth, is

\[ \boxed{13.09}. \]