In circle L with m, angle, K, L, M, equals, 90, degreesm∠KLM=90


and K, L, equals, 6KL=6 units, find the length of arc, K, M
KM

. Round to the nearest hundredth.

1 answer

To find the length of the arc \( \overset{\frown}{KM} \) in circle \( L \), we first need to find the measure of the angle that subtends the arc at the center of the circle (which is angle \( KLM \)).

  1. Find the radius of the circle: The arc \( \overset{\frown}{KM} \) is subtended by angle \( KLM = 90^\circ \), and we know \( KL = 6 \) units. Since \( L \) is the center of the circle, \( KL \) is the radius of the circle \( L \). Therefore:

    \[ r = KL = 6 \text{ units} \]

  2. Find the circumference of the circle: The circumference \( C \) of a circle is given by the formula:

    \[ C = 2\pi r \]

    Substituting the radius into the formula:

    \[ C = 2\pi(6) = 12\pi \text{ units} \]

  3. Determine the fraction of the circle represented by the angle: The angle \( KLM = 90^\circ \) is a quarter of a full circle. Therefore, the fraction of the circle for \( \overset{\frown}{KM} \) is:

    \[ \text{Fraction} = \frac{90^\circ}{360^\circ} = \frac{1}{4} \]

  4. Calculate the length of arc \( \overset{\frown}{KM} \): The length of the arc can be calculated by taking the fraction of the circumference that corresponds to the angle \( KLM \):

    \[ \text{Length of arc } \overset{\frown}{KM} = \text{Fraction} \times C = \frac{1}{4} \times 12\pi \]

    Simplifying this:

    \[ \text{Length of arc } \overset{\frown}{KM} = 3\pi \text{ units} \]

  5. Approximate the length: Using \( \pi \approx 3.14 \), we can find an approximate value:

    \[ 3\pi \approx 3 \times 3.14 \approx 9.42 \text{ units} \]

Therefore, the length of arc \( \overset{\frown}{KM} \) is approximately \( \boxed{9.42} \) units when rounded to the nearest hundredth.