Question
If Talia spins a spinner with 26 equal spaces (labeled A to Z), what is the theoretical probability that she lands on any letter in the word “Mississippi”?(1 point)
Responses
313
Start Fraction 3 over 13 End Fraction
23
Start Fraction 2 over 3 End Fraction
16
Start Fraction 1 over 6 End Fraction
213
Responses
313
Start Fraction 3 over 13 End Fraction
23
Start Fraction 2 over 3 End Fraction
16
Start Fraction 1 over 6 End Fraction
213
Answers
GPT-4o mini
To find the theoretical probability that Talia lands on any letter in the word "Mississippi," we first need to identify the unique letters in the word and their frequencies:
- M: 1
- I: 4
- S: 2
- P: 2
Now, the unique letters are M, I, S, and P. Since the spinner has 26 equal spaces (A to Z), the total number of outcomes is 26.
Next, we calculate the total number of successful outcomes, which is the total number of times the letters in "Mississippi" appear:
- M appears 1 time
- I appears 4 times
- S appears 2 times
- P appears 2 times
Counting these, we get:
1 + 4 + 2 + 2 = 9
Now, we can calculate the probability of landing on any letter from "Mississippi":
\[
\text{Probability} = \frac{\text{Number of successful outcomes}}{\text{Total number of outcomes}} = \frac{9}{26}
\]
Now let's compare this fraction to the given options:
- \( \frac{3}{13} \) is equivalent to \( \frac{9}{26} \) (since 3 times 2 is 6)
- \( \frac{2}{3} \) is not the same.
- \( \frac{1}{6} \) is not the same.
- \( \frac{2}{13} \) is not the same.
Thus, the correct answer is:
\[
\frac{3}{13}
\]
- M: 1
- I: 4
- S: 2
- P: 2
Now, the unique letters are M, I, S, and P. Since the spinner has 26 equal spaces (A to Z), the total number of outcomes is 26.
Next, we calculate the total number of successful outcomes, which is the total number of times the letters in "Mississippi" appear:
- M appears 1 time
- I appears 4 times
- S appears 2 times
- P appears 2 times
Counting these, we get:
1 + 4 + 2 + 2 = 9
Now, we can calculate the probability of landing on any letter from "Mississippi":
\[
\text{Probability} = \frac{\text{Number of successful outcomes}}{\text{Total number of outcomes}} = \frac{9}{26}
\]
Now let's compare this fraction to the given options:
- \( \frac{3}{13} \) is equivalent to \( \frac{9}{26} \) (since 3 times 2 is 6)
- \( \frac{2}{3} \) is not the same.
- \( \frac{1}{6} \) is not the same.
- \( \frac{2}{13} \) is not the same.
Thus, the correct answer is:
\[
\frac{3}{13}
\]