Asked by Leslie
1.The square of x is equal to 4 times the square od y. If x is 1 more than twice y, what is the value of x?
A) -4
B) -.5
C) -.25
D) .25
E) .5
2.In the xy-coordinate plane, lines L an Q are perpendicular. If line L contains the points (0,0) and (2,1), and line Q contains the points ( 2,1) AND (0,T) What is the value of T?
A)-3
B)-2
C)2
D)3
E)5
3. For all positivw integers x, let xÄ
be defined to be (x-1)(x+1). Which of the following is equal to 6Ä-5Ä?
A)2Ä= 1Ä
B)3Ä= 2Ä
C)4Ä= 3Ä
D)5Ä= 4Ä
E)6Ä= 5Ä
A) -4
B) -.5
C) -.25
D) .25
E) .5
2.In the xy-coordinate plane, lines L an Q are perpendicular. If line L contains the points (0,0) and (2,1), and line Q contains the points ( 2,1) AND (0,T) What is the value of T?
A)-3
B)-2
C)2
D)3
E)5
3. For all positivw integers x, let xÄ
be defined to be (x-1)(x+1). Which of the following is equal to 6Ä-5Ä?
A)2Ä= 1Ä
B)3Ä= 2Ä
C)4Ä= 3Ä
D)5Ä= 4Ä
E)6Ä= 5Ä
Answers
Answered by
bobpursley
Do you have any thinking on these? Surely you do not want us to give you answers.
Answered by
Leslie
1. X^2= 4Y^2 and x=2y+1
Sooo i substitute
(2y+1)^2= 4y^2
Find the square root of both sides
2y+1= 4y
Solve for y
2y+1=4y
1=4y
.25=y
Substitue into X=2y=1
x=2(.25)+1
x=.5+1
x=1.5
But that's not an option.What did i do wrong?
Sooo i substitute
(2y+1)^2= 4y^2
Find the square root of both sides
2y+1= 4y
Solve for y
2y+1=4y
1=4y
.25=y
Substitue into X=2y=1
x=2(.25)+1
x=.5+1
x=1.5
But that's not an option.What did i do wrong?
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