To determine if the point \((1, 3)\) is a solution to the equation \(y = \frac{3}{2}x - 1\), we need to substitute \(x = 1\) and \(y = 3\) into the equation and see if it holds true.
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Substitute \(x = 1\) into the equation: \[ y = \frac{3}{2}(1) - 1 \] \[ y = \frac{3}{2} - 1 \] \[ y = \frac{3}{2} - \frac{2}{2} = \frac{1}{2} \]
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Now we have \(y = \frac{1}{2}\) when \(x = 1\), but we substituted the values from the point \((1, 3)\), where \(y = 3\).
Since \(y = 3\) does not equal \(\frac{1}{2}\), the equation is NOT true for this point.
Therefore, the correct answer is: No, because when you substitute 1 for x and 3 for y, the equation is NOT true.