Is (−3, −5) on the line created by y=

3
−1

x−6? How do you know?

Yes, because when you substitute −3 for x and −5 for y, the equation is true.

No, because when you substitute −5 for x and −3 for y, the equation is NOT true.

Yes, because when you substitute −5 for x and −3 for y, the equation is true.

No, because when you substitute −3 for x and −5 for y, the equation is NOT true.

1 answer

To determine if the point \((-3, -5)\) is on the line represented by the equation \(y = \frac{3}{-1}x - 6\), we need to substitute \(x = -3\) and check if the resulting \(y\) value is \(-5\).

First, simplify the equation \(y = \frac{3}{-1}x - 6\):

\[ y = -3x - 6 \]

Now, substitute \(-3\) for \(x\):

\[ y = -3(-3) - 6 \]

This simplifies to:

\[ y = 9 - 6 = 3 \]

Now we see that when \(x = -3\), \(y\) evaluates to \(3\), not \(-5\). Therefore, the point \((-3, -5)\) is not on the line.

The correct response is:

No, because when you substitute −3 for x and −5 for y, the equation is NOT true.