Is (−4, −1) a solution to the equation y=−

4
1

x−2? How do you know?

No, because when you substitute −1 for x and −4 for y, the equation is NOT true.

Yes, because when you substitute −1 for x and −4 for y, the equation is true.

No, because when you substitute −4 for x and −1 for y, the equation is NOT true.

Yes, because when you substitute −4 for x and −1 for y, the equation is true.

1 answer

To determine if the point \((-4, -1)\) is a solution to the equation \(y = -\frac{4}{1}x - 2\), we need to substitute \(x = -4\) and \(y = -1\) into the equation and check if both sides are equal.

We start with the equation:

\[ y = -4x - 2 \]

Now, substitute \(x = -4\):

\[ y = -4(-4) - 2 \]

Calculate the right side:

\[ y = 16 - 2 \] \[ y = 14 \]

Now, we compare this with the value of \(y\) we have, which is \(-1\). Since \(14 \neq -1\), the point \((-4, -1)\) does not satisfy the equation.

Thus, the correct answer is:

No, because when you substitute −4 for x and −1 for y, the equation is NOT true.