Asked by Emili
What are the values of b which satisfy b- square root of 1-1996b=1?
Answers
Answered by
Henry
b - sqrt(1 - 1996b) = 1,
Isolate the radical:
b - 1 = sqrt(1 - 1996b),
Square both sides:
b^2 - 2b + 1 = 1 - 1996b,
b^2 - 2b + 1996b = 1 - 1,
b^2 + 1994b = 0,
Factor out b:
b(b + 1994) = 0,
b = 0,
b + 1994 = 0,
b = -1994,
Solution set: b = 0, and b = -1994.
Isolate the radical:
b - 1 = sqrt(1 - 1996b),
Square both sides:
b^2 - 2b + 1 = 1 - 1996b,
b^2 - 2b + 1996b = 1 - 1,
b^2 + 1994b = 0,
Factor out b:
b(b + 1994) = 0,
b = 0,
b + 1994 = 0,
b = -1994,
Solution set: b = 0, and b = -1994.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.