What are the values of b which satisfy b- square root of 1-1996b=1?

Answer 1

b - sqrt(1 - 1996b) = 1,
Isolate the radical:
b - 1 = sqrt(1 - 1996b),
Square both sides:
b^2 - 2b + 1 = 1 - 1996b,
b^2 - 2b + 1996b = 1 - 1,
b^2 + 1994b = 0,
Factor out b:
b(b + 1994) = 0,
b = 0,
b + 1994 = 0,
b = -1994,

Solution set: b = 0, and b = -1994.