Question

calculate the number of mol of NaHCO3 in 2,2g of baking soda

Answer 1

To calculate the number of moles of sodium bicarbonate (NaHCO₃) in 2.2 grams of baking soda, we first need to know the molar mass of NaHCO₃.

The molar mass can be calculated as follows:

- Sodium (Na): 22.99 g/mol
- Hydrogen (H): 1.01 g/mol
- Carbon (C): 12.01 g/mol
- Oxygen (O): 16.00 g/mol (4 Oxygen atoms)

So, the molar mass of NaHCO₃ is:

\[
\text{Molar mass of NaHCO₃} = 22.99 + 1.01 + 12.01 + (4 \times 16.00)
\]
\[
= 22.99 + 1.01 + 12.01 + 64.00
\]
\[
= 100.01 \, \text{g/mol}
\]

Now we can calculate the number of moles in 2.2 grams of NaHCO₃ using the formula:

\[
\text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}
\]

\[
\text{Number of moles} = \frac{2.2 \, \text{g}}{100.01 \, \text{g/mol}} \approx 0.022 \, \text{mol}
\]

So, there are approximately **0.022 moles** of NaHCO₃ in 2.2 grams of baking soda.