calculate the number of mol of NaHCO3 in 2,2g of baking soda

1 answer

To calculate the number of moles of sodium bicarbonate (NaHCO₃) in 2.2 grams of baking soda, we first need to know the molar mass of NaHCO₃.

The molar mass can be calculated as follows:

  • Sodium (Na): 22.99 g/mol
  • Hydrogen (H): 1.01 g/mol
  • Carbon (C): 12.01 g/mol
  • Oxygen (O): 16.00 g/mol (4 Oxygen atoms)

So, the molar mass of NaHCO₃ is:

\[ \text{Molar mass of NaHCO₃} = 22.99 + 1.01 + 12.01 + (4 \times 16.00) \] \[ = 22.99 + 1.01 + 12.01 + 64.00 \] \[ = 100.01 , \text{g/mol} \]

Now we can calculate the number of moles in 2.2 grams of NaHCO₃ using the formula:

\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]

\[ \text{Number of moles} = \frac{2.2 , \text{g}}{100.01 , \text{g/mol}} \approx 0.022 , \text{mol} \]

So, there are approximately 0.022 moles of NaHCO₃ in 2.2 grams of baking soda.