If you toss two coins simultaneously, what is the probability of getting exactly one head? Write your answer in the simplest form of fraction. (1 point) 2/8 1/4 1/2 1/8

Answer 1

To find the probability of getting exactly one head when tossing two coins, we first need to determine the total number of possible outcomes and the number of favorable outcomes.

When tossing two coins, the possible outcomes are:

1. Heads (H), Heads (H)
2. Heads (H), Tails (T)
3. Tails (T), Heads (H)
4. Tails (T), Tails (T)

Thus, the total number of outcomes is 4.

Now, we need to identify the outcomes with exactly one head:

1. Heads (H), Tails (T)
2. Tails (T), Heads (H)

There are 2 outcomes that result in exactly one head.

Now we can calculate the probability: \[ \text{Probability of getting exactly one head} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{2}{4} = \frac{1}{2} \]

Thus, the probability of getting exactly one head when tossing two coins is \(\frac{1}{2}\).