Use the image to answer the question.

A coordinate plane with four quadrants shows the x-axis ranging from negative 10 to 10 in increments of 1 and the y-axis ranging from negative 5 to 15 in increments of 1. A solid line and a dotted line intersect each other. The equation of the solid line is y equals 4 x minus 10. The equation of the dotted line is y equals negative 2 x plus 8. The intersection point of both lines is shown at positive 3 on the x-axis and positive 2 on the y-axis in quadrant 1.

Review the graphs of a system of these two linear equations in two variables: y=4x−10
and y=−2x+8
Find the solution of the system.

(1 point)

1 answer

The solution to the system of equations represented by the lines \( y = 4x - 10 \) and \( y = -2x + 8 \) is the point where the two lines intersect. According to the information provided, this intersection point is at \( (3, 2) \).

To confirm, you can substitute \( x = 3 \) into both equations:

  1. For the solid line \( y = 4x - 10 \): \[ y = 4(3) - 10 = 12 - 10 = 2 \]

  2. For the dotted line \( y = -2x + 8 \): \[ y = -2(3) + 8 = -6 + 8 = 2 \]

Both equations yield \( y = 2 \) when \( x = 3 \), showing that the intersection point \( (3, 2) \) is indeed the solution of the system.

Thus, the solution of the system is: \[ (3, 2) \]