To determine which graph shows that the linear system given has an infinite number of solutions, we need to recognize that this occurs when the two equations represent the same line. For two equations to be the same line, they must be parallel and coincide exactly, which means they have the same slope and y-intercept.
Now, let’s analyze the equations:
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Equation 1: \(-2x + y = 6\)
- Rearranging it to slope-intercept form (y = mx + b): \[ y = 2x + 6 \]
- The slope is \(2\) and the y-intercept is \(6\).
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Equation 2: \(4x - 2y = -12\)
- Rearranging it: \[ -2y = -4x - 12 \quad \Rightarrow \quad 2y = 4x + 12 \quad \Rightarrow \quad y = 2x + 6 \]
- Again, the slope is \(2\) and the y-intercept is \(6\).
Since both equations simplify to the same equation \(y = 2x + 6\), this means that they represent the same line and therefore the system has an infinite number of solutions, as every point on the line is a solution.
Looking at the responses:
- The first option describes two parallel lines, which indicates the system has no solutions.
- The second option describes intersecting lines, which indicates a unique solution.
- The third option describes only one line, which would indicate that it has infinitely many solutions.
- The fourth option also describes only one line, which would indicate that it has infinitely many solutions.
Therefore, the correct answer that shows the linear system has an infinite number of solutions is the third option, where only one line is plotted on the graph.