To solve the compound inequality \(60 + 8 \leq -10\) or \(8C + 12 > 20\), we will solve each part separately.
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First Inequality: \[ 60 + 8 \leq -10 \] Simplifying the left side: \[ 68 \leq -10 \] This inequality is false. There are no values of \(C\) that satisfy this part of the inequality.
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Second Inequality: \[ 8C + 12 > 20 \] Subtracting 12 from both sides: \[ 8C > 20 - 12 \] \[ 8C > 8 \] Dividing both sides by 8: \[ C > 1 \]
Since the first inequality is false, we only consider the solution from the second inequality.
Thus, the solution to the compound inequality is: \[ C > 1 \]