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What are the solutions for the equation for x squared minus 2x + 2 - 3x - x squared = 0

Put the smaller x value in the first box right in your answer as simple by fractions or whole numbers only
x = __,___

1 answer

First, let's simplify the equation:

Starting with \( x^2 - 2x + 2 - 3x - x^2 = 0 \):

  1. Combine like terms: \[ x^2 - x^2 - 2x - 3x + 2 = 0 \] This simplifies to: \[ -5x + 2 = 0 \]

  2. Now, isolate \( x \) by moving \( 2 \) to the other side: \[ -5x = -2 \]

  3. Divide by \(-5\): \[ x = \frac{2}{5} \]

Since this is a linear equation, there is only one solution, which is \( x = \frac{2}{5} \).

Thus, the solution in the specified format is: \[ x = \frac{2}{5}, \frac{2}{5} \]

So, the answer is: \[ x = \frac{2}{5}, \frac{2}{5} \]